Logic/De Morgan's laws

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(Created page with 'Logic > De Morgan's laws == Contents == * Category:Mathematical logic(Wikipedia) * [[wikipedia:Boolean_algebra_(logic)|Boole…')
 
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* [[wikipedia:Boolean_algebra_(logic)|Boolean algebra (logic)]]
* [[wikipedia:Boolean_algebra_(logic)|Boolean algebra (logic)]]
* [[wikipedia:De_Morgan%27s_laws|De_Morgan's laws]]
* [[wikipedia:De_Morgan%27s_laws|De_Morgan's laws]]
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== Overview ==
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=== Definition of De Morgan's laws by truth table ===
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0 means false, 1 means true, and ≡ means equivalent.
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Case of "¬(P∧Q)" ≡ "¬P∨¬Q".
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{| border="1" class="wikitable" style="background-color:#ddf"
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! style="background:#ffdead;" | P 
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! style="background:#ffdead;" | Q 
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! style="background:#ffdead;" | P∧Q 
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! style="background:#ffdead;" | ¬P 
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! style="background:#ffdead;" | ¬Q 
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! style="background:#ffdead;" | ¬P∨¬Q 
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! style="background:#ffdead;" | ¬(P∧Q) 
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|-
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| 0
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| 0
 +
| 0
 +
| 1
 +
| 1
 +
| 1
 +
| 1
 +
|-
 +
| 0
 +
| 1
 +
| 0
 +
| 1
 +
| 0
 +
| 1
 +
| 1
 +
|-
 +
| 1
 +
| 0
 +
| 0
 +
| 0
 +
| 1
 +
| 1
 +
| 1
 +
|-
 +
| 1
 +
| 1
 +
| 1
 +
| 0
 +
| 0
 +
| 0
 +
| 0
 +
|-
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|}
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 +
Case of "¬(P∨Q)" ≡ "¬P∧¬Q".
 +
 +
{| border="1" class="wikitable" style="background-color:#ddf"
 +
! style="background:#ffdead;" | P 
 +
! style="background:#ffdead;" | Q 
 +
! style="background:#ffdead;" | P∨Q 
 +
! style="background:#ffdead;" | ¬P 
 +
! style="background:#ffdead;" | ¬Q 
 +
! style="background:#ffdead;" | ¬P∧¬Q 
 +
! style="background:#ffdead;" | ¬(P∨Q) 
 +
|-
 +
| 0
 +
| 0
 +
| 0
 +
| 1
 +
| 1
 +
| 1
 +
| 1
 +
|-
 +
| 0
 +
| 1
 +
| 1
 +
| 1
 +
| 0
 +
| 0
 +
| 0
 +
|-
 +
| 1
 +
| 0
 +
| 1
 +
| 0
 +
| 1
 +
| 0
 +
| 0
 +
|-
 +
| 1
 +
| 1
 +
| 1
 +
| 0
 +
| 0
 +
| 0
 +
| 0
 +
|-
 +
|}
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 +
== CAI Exercise ==
== CAI Exercise ==

Latest revision as of 08:32, 23 May 2014

Logic > De Morgan's laws

Contents

Contents

Overview

Definition of De Morgan's laws by truth table

0 means false, 1 means true, and ≡ means equivalent.

Case of "¬(P∧Q)" ≡ "¬P∨¬Q".

 P   Q   P∧Q   ¬P   ¬Q   ¬P∨¬Q   ¬(P∧Q) 
 0  0  0  1  1  1  1
 0  1  0  1  0  1  1
 1  0  0  0  1  1  1
 1  1  1  0  0  0  0

Case of "¬(P∨Q)" ≡ "¬P∧¬Q".

 P   Q   P∨Q   ¬P   ¬Q   ¬P∧¬Q   ¬(P∨Q) 
 0  0  0  1  1  1  1
 0  1  1  1  0  0  0
 1  0  1  0  1  0  0
 1  1  1  0  0  0  0


CAI Exercise

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